Question

A real gas is subjected to an adiabatic process causing a change in state from (3 bar, SOL, 500 K) to
(5 bar, 40 L, 600 K) against a constant pressure of 5 bar. The magnitude of enthalpy change for the
process is
(A) 100 J
(C) 9000
(D) 10000
(B)0

Answer 1

The magnitude of enthalpy change for the  process is 8000 J.

Explanation:

As we know that

q = 0

P(ext) = 4 bar

ΔU = - P(ext) [ V2 - V1] =  - p (ext) ΔV  = - 4 ( 30 - 40 ) = + 40 L

ΔU = q + w - p ΔV

ΔH = ΔU + ΔPV

Δ(PV) = P2V2 - P1 V1

Δ(PV) = ( 30 x 4 - 40 x 2)

Δ(PV) = 120 - 80

Δ(PV) = 40 + 40 = 80 L bar

ΔH = 80 x 100 J

ΔH = 8000 J

Thus the magnitude of enthalpy change for the  process is 8000 J.

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