Question

A real image, 4/3 size of the object is formed 18cm from the
lens. Calculate the focal length of the lens.​

Answer 1

Answer:

u= 18 cm

Height of image(hi)/Height of the object(ho) = 4/3

hi/ho=v/u

4/3= v/18

v=(4×18)÷3

v= 24 cm

1/f= 1/v - 1/u

1/f = 1/24 -1/18

1/f= 0.0416 - 0.0555

1/f = - 0.0139..

f = - 0.014

HOPE IT HELPS!!!