Physics, asked by Hajaramustapha963, 1 year ago

a real image which is four times the size of the object is produced with a converging lens of focal length 16cm. What is the separation between the object and it's image??

Answers

Answered by masoomptl
1

The lens formula is 1−1=1 where , and are the distance of the image from the mirror , the distance of the object from the mirror and the focal length respectively.

Magnification =ℎℎ=, where ℎ and ℎ are the heights of the image and object respectively.

As per the new Cartesian convention, distances from the mirror toward the side of the object are negative and distances toward the other side are positive. Distances above the principal axis are positive and distances below the principal axis are negative.

⇒ For a converging lens with a real image, is negative, while and are positive.

It is given that the size of the image is three times that of the object.

=⇒−3=⇒=−3.

It is given that the focal length is 15 cm.

1−1=1⇒−13−1=115.

⇒−43=115⇒=−20 cm.

⇒ The distance of the object from the lens is 20 cm.

    HOPE IT HELPS ...

   

Similar questions