Question

A real no.k is a zero of the polynomial f(x) if
(a) f(K) >o
(b) f(k) = 0
(c) f(k)<0
(d) none​

Answer 1

Answer:

let one zero be α then the other will be 1/α  

clearly from the above step we can see that the product of the roots is 1 so c/a=1

4k/k²+4=1

4k=k²+4

k²-4k+4=0

(k-2)(k-2)

hence k=2

Step-by-step explanation: