A real root of the given equation x2 - 16 = 0 lies in the interval
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x=4 answer I wiss it will help
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Given : Equation x^2 - 16 = 0
Find: Interval in which real root of x lies
Solution:
x^2 - 16 = 0
(x - 4) (x + 4) >=0
x = [-4,4]
Hence, The real root of above equation x^2 - 16 = 0 will lie between [-4,4].
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