Question

A rear view mirror of an automobile
has a focal length of 2m. Find the
nature and distance of the image of a
person standing 4m in front of the
mirror.
O
Image is formed at a distance of 1.33 m
and image formed is erect and virtual
0
Image is formed at a distance of 1.5 m
and image formed is erect and virtual
o
Image is formed at a distance of 1.33 m
and image formed is inverted and real
0
Image is formed at a distance of 1.5 m
and image formed is inverted and real​

Answer 1

Answer:

Image is formed at a distance of 1.33 m

and image formed is erect and virtual

Explanation:

Given:-

• object distance = -4 m
• focal length = 2 m

Using the mirror formula,

$\frac{1}{f} = \frac{1}{v} + \frac{1}{u}$

$\frac{1}{2 } = \frac{1}{v} + \frac{1}{ (- 4)}$

$\frac{1}{2 } = \frac{1}{v} - \frac{1}{ 4}$

$\frac{1}{2} + \frac{1}{4} = \frac{1}{v}$

$\frac{2 + 1}{4} = \frac{1}{v}$

$\frac{3}{4} = \frac{1}{v}$

$\boxed{v = \frac{4}{3} \: \: \: or \: \: \: 1.33 }$

Hence option a is correct one.