Math, asked by gulfishaq007, 8 hours ago

A recent study of how Americans spend their leisure time surveyed workers employed more than 5 years. They determined the probability an employee has 2 weeks of vacation time to be 0.45, 1 week of vacation time to be 0.10, and 3 or more weeks to be 0.20. Suppose 20 workers are selected at random.

(a) What is the probability that at most 2 of the workers have 3 or more weeks of vacation time?

Answers

Answered by itzSingle01
0

x2= (3q + 2)2 = (3q)2+22+2×3q×2 = 9q2 + 4 + 12q = 3 (3q2 + 4q + 1)+1= ??

Answered by narsimhac15156
0

Answer:

×2=(3q+2)2=(3q)2+22+2×3q ×2= 9q2+4+12q=(33q2+4q+1)+1=??

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