Math, asked by hellypatel555, 1 year ago

A recipe for 4 servings requires salt and pepper to be added in the ratio of 2:3. If the recipes
adjusted from 4 to 8 servings, what is the ratio of the salt and pepper that must now be added
(a) 4:3
(b) 2:6
(c) 2:3
(d) 3:2​

Answers

Answered by chinmay3199
2

Answer:

A is the answer for your question

Answered by sharonr
11

No change in ratio of the salt and pepper that must now be added and same ratio needs to be added  that is 2 : 3. The correct option is (c)

Solution:

Given that a recipe of 4 servings requires salt and pepper to be added in the ration 2:3. If the recipe is adjusted from 4 to 8 servings what is the ratio of the salt and pepper that must now be added.

Let’s assume for 4 servings total quantity of salt and pepper = 20

So salt for 4 serving = \frac{2}{5} \times 20 = 8

And pepper for 4 serving = \frac{3}{5} \times 20 = 12

Now calculate required quantity for 8 servings.

For 4 servings, total is 20 so for 8 servings total required quantity of salt and pepper = 20 x 2 = 40

So salt for 8 servings = 40 \times \frac{2}{5} = 16

And pepper for 8 serving = 40 \times \frac{3}{5} = 24

So salt need to be added for 8 serving = required salt for 8 serving – present salt for 4 serving  

= 16 – 8 = 8

Similarly pepper need to be added for 8 serving = required pepper for 8 serving – present pepper for 4 serving = 24 – 12 = 12

Required ratio = salt added / pepper added = \frac{8}{12} = \frac{2}{3}

Hence no change in ratio and same ratio needs to be added that is 2 : 3

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