Question

A reclangulas field is such that
length is one and half times breadth b.The perimeter of the field is 200m. Find the sides
of the field.​

Answer 1

Answer:

Step-by-step explanation:

Perimeter of a rectangle = 2(l+b)

Length = 1 1/2 b = 3b/2  breadth = b       Perimeter = 200

2(3b/2 + b) = 200

5b/2 = 200/2 = 100

b = 100×2/5 = 40

b = 40

l = 3b/2 = 60

Answer 2

Answer:

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Step-by-step explanation:

let be length x

so,

width is 1/2x

perimeter of rectangle=2(a+b)

2(x+1/2x)=200m

3x/2=100

x=2×100/3

x=66.66

length=66.66 m

width=99.99