Question

A recoiling gun when fired is stopped by a force, 1N in 1s. Find the velocity with which the bullet of mass, 50g left the barrel of the gun.
Steps plz​

Answer 1

Explanation:

given

m=50g

f=1N

t=1s

v=?

u=0

then the formula = V=u+ft/t

v=0+1×1/50

v=0.02m/s²