Question

A recoiling gun when fired is stopped by a force, 1N in 1s. Find the velocity with which the bullet of mass, 50g left the barrel of the gun. Steps plz​

Answer 1

Answer:

-0.50 m/s

Explanation:

Let the recoil velocity of gun be V.

Mass of gun M

gun

=5.0 kg

Mass of bullet M

bullet

=0.01 kg

Velocity of bullet V

bullet

=250 m/s

Initial momentum of the system P

i

=0

Applying the conservation of linear momentum : P

f

=P

i

Or M

gun

V+M

bullet

V

bullet

=0

Or 5×V+0.01×250=0

⟹ V=−0.5 m/s

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