Question

A rectangle and a square are of equal area. If the length and the perimeter of a rectangle are 25 cm and 58 cm, respectively, then find the perimeter and area of the square.​

Answer 1

Answer:

40, 100

Step-by-step explanation:

length of rectangle= 25cm

perimeter= 58cm

breadth= b

also, perimeter= 2(l+b)

= 58= 2(25+b)

= 58/2 = 25+b

= 29= 25+b

= b= 29-25= 4cm

area of rectangle = l×b= 25×4 = 100cm^2

according to question, area of rectangle= area of square

so area of square= 100cm^2

area of square = side^2

100 = side^2

so, side = √100 = 10cm

perimeter of square= 4× side = 4×10 = 40 cm

therefore, perimeter and area of square is 40 cm and 100cm^2 respectively

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Answer 2

Step-by-step explanation:

Let thelength of rectangle =l=25cm Breath=bcm Side of square=acm Area of square=are of rectangle a 2 = l b − ( 1 ) a2=lb-(1) Perimeter=2(l+b)=58 l+b=29 b=4 cm Area of square ( a 2 ) = l b = 25 ⋅ 4 = 100 c m 2 (a2)=lb=25⋅4=100cm2 a = 10 c m a=10cm Perimeter of square=4a 4 ⋅ 10 = 10 c m 4⋅10=10cm.Read more on Sarthaks.com - https://www.sarthaks.com/1119208/rectangle-square-equal-area-length-perimeter-rectangle-respectively-then-find-perimeter