A rectangle and a square have the same perimeter 100 cm. Find the side of the square. If the rectangle has a breadth 2 cm less than that of the square. Find the breadth, length and area of the rectangle.
Answers
Step-by-step explanation:
solution :-
Given
perimeter of rectangles = perimeter of square = 100cm
Find the side of a square :-
perimeter of the square = 4× side
=> 100 cm = 4× side
=> side = 100/ 4 cm
=> 25 cm
Breadth of a rectangle = ( side of square - 2) cm
= (25-2) cm
= 23 cm
let the length of the rectangle be X
find the length of the rectangle:-
perimeter of rectangles = 2(l+b)
100 = 2( X+23) cm
100/2 = X + 23 cm
50 - 23 cm
27 cm
Find the area of a rectangle :-
Area = length × breadth
Area = (27×23) cm²
Area = 621 cm ²
Hence,
length of the rectangle = 27 cm
Area of the rectangle = 621 cm ²
__________
mark brainliest
___________
☆ @tamalikaroy24
Answer:
Step-by-step explanation:
solution :-
Given
perimeter of rectangles = perimeter of square = 100cm
Find the side of a square :-
perimeter of the square = 4× side
=> 100 cm = 4× side
=> side = 100/ 4 cm
=> 25 cm
Breadth of a rectangle = ( side of square - 2) cm
= (25-2) cm
= 23 cm
let the length of the rectangle be X
find the length of the rectangle:-
perimeter of rectangles = 2(l+b)
100 = 2( X+23) cm
100/2 = X + 23 cm
50 - 23 cm
27 cm
Find the area of a rectangle :-
Area = length × breadth
Area = (27×23) cm²
Area = 621 cm ²
Hence,
length of the rectangle = 27 cm
Area of the rectangle = 621 cm ²
Step-by-step explanation:
mark me brainliest