Question

A rectangle and a square have the same perimeter 100 cm. Find the side of the square. If the rectangle has a breadth 2 cm less than that of the side of the square. Find the breadth, length and area of the rectangle.​

Answer 1

Answer:

square=4a=100cm

rectangle= 2(l+b)=100cm

side of square=25cm

breadth of rectangle=25-2=23

2(l+b)=100

l+23=100/2=50

l=50/23

l=27

area=l*b

=27*23=621

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Step-by-step explanation:

Answer 2

Answer:

$area \: of \: rectangle = 966 \: {cm}^{2} \\ \\ area \: of \: square = 25 \times 25 = 625 \: {cm}^{2} .$

l=48-25= 23 cm

b= 50-23=27 cm

side of square= 25 square cm

Step-by-step explanation:

$perimeter = 100 \: cm \\ 4a = 100 \\ a = 25\\ \\ l + b =50 \\ l = 50 - b \\ 100 = 2(l + b)\\ b = a - 2 \\l = 50 - a - 2 \\ l = 48 - a \\ \\ (l) (l - 2)= a \times a \\ \\ \\ \\ \\ (48 - a)(48 - a - 2) \\ \\ (48 - a)(46 - a) = (48 - 25)(46 - 25) = (23)(21) = 23 \times 21 = 483 \: {cm}^{2} \\ \\ area \: of \: rectangle = 483 \: {cm}^{2} \\ \\ area \: of \: square = 25 \times 25 = 625 \: {cm}^{2} .$

l=48-25= 23 cm

b= 50-23=27 cm

side of square= 25 square cm