a rectangle and a square have the same perimeter of 80 m . if the lenght of the rectangle is 6 m more than the breadth , find the area of the rectangle
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let the length of rectangle be l m then its breadth = (l-6) m
according to the question
perimeter of square =perimeter of rectangle = 80m
4 side = 2(l+b)=80
4 l=2(l +(l-6) ) m
4 l= 2 l+2 l- 12= 80 m
4 l- 12=80
4 l= 80+12
l=92/4
l =23 m
and b= l- 6 = 23- 6
b= 17 m
so area of rectangle = l × b = 23 × 17=391 m
according to the question
perimeter of square =perimeter of rectangle = 80m
4 side = 2(l+b)=80
4 l=2(l +(l-6) ) m
4 l= 2 l+2 l- 12= 80 m
4 l- 12=80
4 l= 80+12
l=92/4
l =23 m
and b= l- 6 = 23- 6
b= 17 m
so area of rectangle = l × b = 23 × 17=391 m
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