A rectangle block is 9m long, 5m wide and 3m high. Find the cost of colouring its surface area at 50 paise per sq. m.?
Answers
surface area of block=height*breadth*length
=5*3*9
➡135m^3
cost of colouring the surface area
=135×0.5(50 paise)
➡67.5 rs
So the cost of colouring the surface is 67.5 rs...
Answer:
- The cost of coloring is ₹107.
Step-by-step explanation:
Given that,
- A rectangular block (cuboid-shaped) of dimension 9m × 3m × 5m.
Here, the block's surface is to be colored at the rate of 50paise per m². So, we need to find it's total cost.
Step 1 :
Finding it surface area :
➪ Surface area of the block is given by :
→ 2(lb + bh + lh)
We have,
- l (length) = 9m.
- b (breadth) = 3m.
- h (height) = 5m.
From the given dimensions :
→ Surface area of the block :
→ 2(9*3 + 3*5 + 9*5)
→ 2(27 + 35 + 45)
→ 2(107)
→ 214m²
- The surface area of the block is 214m²
Step 2 :
Finding the total cost of coloring :
➪ Total cost of coloring the block :
→ rate of coloring × surface area of the block.
- Rate is 50 paise or, ₹0.50 per metre² (given)
- Surface area = 214m²
So,
Total cost of coloring = 214 × 0.50
= ₹107
∴ The cost of coloring is ₹107