A rectangle circusmbing in a circpe the it is a square prove
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As lengths of the two tangents drawn from an external point to a circle are equal. Therefore, adjacent sides of ABCD are equal. Rectangle with equal adjacent sides is a square. Hence, ABCD is a square.❤️❤️
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Answer:
A rectangle ABCD curcumscribe a circle which touches the circle at P, Q, R, S.
To Prove:
ABCD is a square.
Proof:
As tangents from external point are equal.
AP = AS−−−−−−−−−−−(1)
PB = BQ −−−−−−−−−−(2)
DR = DS−−−−−−−−−−(3)
RC = QC−−−−−−−−−−(4)
Add (1), (2), (3) and (4)
AP+PB+DR+RC = AS +BQ+DS+QC
AB +CD=AD+BC
2AB =2BC
Adjacent sides are equal so ABCD is a square.
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