A rectangle field has 80m length and 48m breadth. Three roads,each of width 2 m pass through the field such that two roads are parallel to the breadth and the third road parallel to the length. Find the area covered by the three roads.
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the 2 roads parallel to the breadth have equal area
total area of the 2 roads is 2(2*48)
=192m^2
area of third road is 2*80=160m^2
there are 2 parts common in the roads....(refer the diagram)....
area of the 2 parts are same ...
area of the 2 parts is 4+4= 8m^2
then the total area of three roads :-
(192+160)-8=352-8=344 m^2
Hi friend ....I gave you the answer and helped you now please you help me by marking brainliest.... remember I answered first
total area of the 2 roads is 2(2*48)
=192m^2
area of third road is 2*80=160m^2
there are 2 parts common in the roads....(refer the diagram)....
area of the 2 parts are same ...
area of the 2 parts is 4+4= 8m^2
then the total area of three roads :-
(192+160)-8=352-8=344 m^2
Hi friend ....I gave you the answer and helped you now please you help me by marking brainliest.... remember I answered first
milton1:
348
no
the same sum was in op sinhal bokk
of your school
in our book it is 344
please send me
leave the answer i guess you understood
ok
plz mark me brainliest
i gave u process
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0
Your is all about easy. To me the answer is in front of you.
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