Question

A rectangle field is 40 m wide by 90 m long how long is the diagonal path connecting the two opposite coeners of the field

Answer 1

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DIMENSIONS OF FIELD : -

$l = 90m$

$b = 40m$

THE DIAGONAL INSIDE THE RECTANGLE WILL DIVIDE IT INTO 2 HALVES AND EACH WOULD BE A RIGHT ANGLED TRIANGLE.

THE DIAGONAL WILL BE THE HYPOTENUSE OF THAT TRIANGLE, AND THE “l = 90m” and “b = 40m” WOULD BE ITS LEGS.

SO BY PYTHAGOREAN THEOREM :

${l}^{2} + {b}^{2} = {d}^{2}$

${(90)}^{2} + {(40)}^{2} = {d}^{2}$

OR WE CAN SAY THAT,

$d = \sqrt{ {90}^{2} + {40}^{2} }$

$d = \sqrt{8100 + 1600}$

$d = \sqrt{9700}$

$d = 98.48m$