a rectangle hall is 50m long and 12m wide. its floor is to be covered with square tiles, each of the side 25cm. find the number of tiles that are used to cover the floor and also find the cost of tiles required at the rate of rupees 5 per tile.
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Answer:
Number of tiles required are 9600, cost per tile is rupees 48000.
Step-by-step explanation:
Length of the rectangular hall = 50m
Width of the rectangular hall = 12m
Area of the rectangular hall = length × width = 50×12 = 600m^2
Measurement of one side of a square tile = 25cm = 0.25m
Area of one square tile = side^2 = 0.25×0.25 = 0.0625m^2
No.of tiles required = area of the rectangular hall / area of one square tile
= 600m^2 / 0.0625m^2
= 9600 tiles.
Cost of one tile = rupees 5
Cost of 9600 tiles = 9600 × 5
= rupees 48000.
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