Question

A rectangle has a diagonal that is 3.6 feet longer than the length and 7.1 feet longer than the width. What are the dimensions of the rectangle? I would appreaciate it if someone could help me solve this problem. This is what I've done so far but I know its not correct. Thank you for your time.
X^2 + (X+7.1)^2 = (X+3.6)^2
X^2 + X^2 + 14.2 + 50.41 = X^2 + 2X + 3.6
X^2+16.2X + 52.6=0
(X=13.15)(X=4.05)

Answer 1

Answer:

diagonal=17.7 ft, length=14.1ft and

breadth=10.6 ft are the dimensions

of the rectangle