A rectangle has a height of 3 and a width of 2x^2+3x-52x 2 +3x−5
Answers
Answer:
Here the quadratic equation is 2x
Here the quadratic equation is 2x 2
Here the quadratic equation is 2x 2 −3x+5=0
Here the quadratic equation is 2x 2 −3x+5=0Comparing it with ax
Here the quadratic equation is 2x 2 −3x+5=0Comparing it with ax 2
Here the quadratic equation is 2x 2 −3x+5=0Comparing it with ax 2 +bx+c=0, we get
Here the quadratic equation is 2x 2 −3x+5=0Comparing it with ax 2 +bx+c=0, we geta=2,b=−3,c=5
Here the quadratic equation is 2x 2 −3x+5=0Comparing it with ax 2 +bx+c=0, we geta=2,b=−3,c=5Therefore, discriminant, D=b
Here the quadratic equation is 2x 2 −3x+5=0Comparing it with ax 2 +bx+c=0, we geta=2,b=−3,c=5Therefore, discriminant, D=b 2
Here the quadratic equation is 2x 2 −3x+5=0Comparing it with ax 2 +bx+c=0, we geta=2,b=−3,c=5Therefore, discriminant, D=b 2 −4ac
Here the quadratic equation is 2x 2 −3x+5=0Comparing it with ax 2 +bx+c=0, we geta=2,b=−3,c=5Therefore, discriminant, D=b 2 −4ac(−3)
Here the quadratic equation is 2x 2 −3x+5=0Comparing it with ax 2 +bx+c=0, we geta=2,b=−3,c=5Therefore, discriminant, D=b 2 −4ac(−3) 2
Here the quadratic equation is 2x 2 −3x+5=0Comparing it with ax 2 +bx+c=0, we geta=2,b=−3,c=5Therefore, discriminant, D=b 2 −4ac(−3) 2 −4×2×5
Here the quadratic equation is 2x 2 −3x+5=0Comparing it with ax 2 +bx+c=0, we geta=2,b=−3,c=5Therefore, discriminant, D=b 2 −4ac(−3) 2 −4×2×5=9−40
Here the quadratic equation is 2x 2 −3x+5=0Comparing it with ax 2 +bx+c=0, we geta=2,b=−3,c=5Therefore, discriminant, D=b 2 −4ac(−3) 2 −4×2×5=9−40=−31
Here the quadratic equation is 2x 2 −3x+5=0Comparing it with ax 2 +bx+c=0, we geta=2,b=−3,c=5Therefore, discriminant, D=b 2 −4ac(−3) 2 −4×2×5=9−40=−31Here, D<0
Here the quadratic equation is 2x 2 −3x+5=0Comparing it with ax 2 +bx+c=0, we geta=2,b=−3,c=5Therefore, discriminant, D=b 2 −4ac(−3) 2 −4×2×5=9−40=−31Here, D<0Therefore the equation has no real roots.
Step-by-step explanation:
Hope it helps you.