Question

a rectangle has a height of 4 and a width of x^2+3x+2

Answer 1

Answer:

width of the rectangle = x^2+3x+2

= x^2+(2+1)x+2

=x^2+2x+x+2

. = x(x+2) +1(x+2)

= (x+2)(x+1)

height =4