A rectangle has a height of 555 and a width of 4x^2-2x-64x 2
−2x−64, x, squared, minus, 2, x, minus, 6.
Answers
The correct formatted question is,
A rectangle has a height of 5 and a width of 4x^2-2x-6. Find the area of rectangle.
Find the area of rectangle.
Given:
A rectangle has a height of 5 and a width of 4x^2-2x-6.
To find:
Area of rectangle.
Solution:
The area of rectangle is given by,
Area = length × width.
∴ Area = 5 × (4x² - 2x - 6)
= 5 × 4x² - 5 × 2x - 5 × 6
= 20x² - 10x - 30
Therefore, the area of rectangle is 20x² - 10x - 30.
Upon solving the above quadratic equation, we get,
20x² - 10x - 30 = 0
2x² - x - 3 = 0
x = 3/2, x = -1
Therefore, the area of rectangle is,
Area = 20x² - 10x - 30
⇒ Area = 20 (3/2)² - 10 (3/2) - 30
= 20 (9/4) - 5 (3) - 30
= 5 (9) - 15 - 30
= 45 - 15 - 30
= 0
Therefore, the area of rectangle is,
Area = 20x² - 10x - 30
⇒ Area = 20 (-1)² - 10 (-1) - 30
= 20 (1) + 10 - 30
= 20 - 20
= 0
Answer:12
Step-by-step explanation:
Multiply 5 by all the numbers