Math, asked by of3002413, 1 day ago

A rectangle has a height of t 2 + 7 t + 6 t 2 +7t+6t, squared, plus, 7, t, plus, 6 and a width of 2 t + 1 2t+12, t, plus, 1.

Answers

Answered by nega95
2

Answer:

62t

3

+15t

2

+19t+6

Step-by-step explanation:

Height of the Rectangle=t^2+7t+6=t

2

+7t+6

Width of the Rectangle=2t+1=2t+1

Area of the Rectangle = Height X Width

\begin{gathered}=(2t+1)(t^2+7t+6)\\=2t(t^2+7t+6)+1(t^2+7t+6)\\=2t^3+14t^2+12t+t^2+7t+6\\$Collect like terms\\=2t^3+14t^2+t^2+12t+7t+6\\Area=2t^3+15t^2+19t+6\\\end{gathered}

The area of the rectangle is 2t^3+15t^2+19t+62t

3

+15t

2

+19t+6

hope it helps make me as brainlist

Similar questions