Question

a rectangle has a height of x+9 and a width of x^2+2x find area of rectangle

Answer 1

Answer:

area = length*width

=(x+9)(x^2+2x)

=x^3+11x^2+18x

Step-by-step explanation:

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Answer 2

Answer:

area=x³+11x²+18x

Step-by-step explanation:

height of a rectangle=(x+9)

width of rectangle=(x²+2x)

as we know,

area of rectangle= length x width/breadth

so area = (x+9) X (x²+2x)

             =x(x²+2x)+9(x²+2x)

              =x³+11x²+18x

area of rectangle is x³+11x²+18x

if we simply then,

x³+11x²+18x

in this situation we can take x common

= x(x²+11x+18)

= x(x²+2x+9x+18)

= x[x(x+2)+9(x+2)]

= x[(x+9)(x+2)]

= x(x+9)(x+2)