Math, asked by shibnariyas0, 10 months ago

A rectangle has a length of (x²+4y³)unit and a breadth of (-2x²+y³)unit . What it its perimeter​

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Answers

Answered by amanraj143
40

Step-by-step explanation:

Hello mate

Here is your answer

Here, length of the given rectangle = (x²+4y³)unit

And, breadth = (-2x²+y³)unit

Then Perimeter of the given rectangle

= 2*(length +breadth)

= 2*( x^2+4y^3+ -2x^2 +y^3)

= 2*(x^2-2x^2 +4y^3 +y^3)

= 2*( -x^2+5y^3)

= -2x^2+10y^3

hope it helps

plz mark me as brainliest

Answered by katrina05sangee
2

Answer:

Step-by-step explanation:

Hello mate

Here is your answer

Here, length of the given rectangle = (x²+4y³)unit

And, breadth = (-2x²+y³)unit

Then Perimeter of the given rectangle

= 2*(length +breadth)

= 2*( x^2+4y^3+ -2x^2 +y^3)

= 2*(x^2-2x^2 +4y^3 +y^3)

= 2*( -x^2+5y^3)

= -2x^2+10y^3

hope it helps

plz mark me as brainliest

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