Question

A rectangle has a length that is 2 less than 3 times the width. If the area of this
rectangle is 16, find the dimensions and the perimeter.​

Answer 1

Step-by-step explanation:

perimeter =lxb

=2x3=6

area=16

.

Answer 2

Answer:

Step-by-step explanation:

Let L = the length of the rectangle and W = its width

A rectangle has a length that is 2 less than 3 times the width:  L = 3W - 2

The area of this rectangle is 16: Area = 16 = L*W

 Substitute 3W-2 for L in the area equation:

 Area = 16 = L*W

16 = (3W-2)*W

16 = 3W2 - 2W

0 = 3W2 - 2W - 16

 Factors to:

 0 = (3W-8)(W+2)

W = 8/3 and -2

 Since we can't have a width of -2, W = 8/3

 L = 3W - 2 = 3*(8/3) - 2 = 6

 Check:

Area = L*W = 6*(8/3) = 48/3 = 16