Question

A rectangle has a length that is 2 less than 3 times the width. If the area of this rectangle is 16, find the dimensions and the perimeter.​

Answer 1

Let x= the length of the rectangle and y= its width

As per the question

x=3y−2

Given ,The area of this rectangle is 16

Solution

Area=xy=16

or

(3y−2)y=16

3y^2−2y−16=0

Factoring

(3y−8)(y+2)=0

Solution

Since we can't have a negative width, y= 8/3

Answer 2

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the perimeter of the rectangle is 52/3 cm.

Explanation:

Let the width(b) of the rectangle be 'x'.

Hence possible values of x can be 8/3 or -2.

Hence,the perimeter of the rectangle is 52/3 cm.