Question

A rectangle has a length that is 6 cm more than the width. Its perimeter is
100 cm . What is the area?

Answer 1

SolutioN :-

Let

• Breadth of rectangle = x
• Length of rectangle = x + 6

★ Perimeter of rectangle = 2 ( L + B )

→ 2 ( x + x + 6 ) = 100

→ 2 ( 2x + 6 ) = 100

→ 4x + 12 = 100

→ 4x = 100 - 12

→ 4x = 88

→ x = 88/4

→ x = 22

Breadth of rectangle = x = 22 cm

Length of rectangle = x + 6 = 28 cm

★ Area of rectangle = L × B

→ 22 × 28

→ 616 cm²

∴ Area of rectangle is 616 cm²

Answer 2

Given :

• Length is 6 cm more than its width / breadth

• Perimeter = 100 cn

To find :

• Area of the Rectangle

According to the question :

• Length = l & Width = w

It is given that, Length is 6 cm more than it's width / breadth,

↦∴ l = 6 + w

↦Perimeter of the Rectangle = 2 ( l + w )

⟹ 100 = 2 (( 6 + w ) + ( w )

⟹ 100 = 2 ( 6 + 2w )

⟹ 100 = 12 + 4w

⟹ 4w = 100 - 12

⟹ 4w = 88

⟹ w = 88 / 4

⟹ w = 22

∴ Width = 22 cm

Length = 6 + w = 6 + 22 = 28 cm

Verification :

↦Perimeter = 2 ( l + b )

100 = 2 ( 28 + 22 )

100 = 2 ( 50 )

∴ 100 = 100

Hence Verified !

Finding Area :

↦Area of the Rectangle = ( l × b )

⟹ ( 28 × 22 )

⟹ 616 cm²

∴ Area of the Rectangle = 616 cm².

So Its Done !!