A rectangle has a length that is 6 cm more than the width. Its perimeter is
100 cm. What is the area?
Answers
Answer:
The answer is 616 cm
Step-by-step explanation:
Length is 6 cm more than its width breadth
• Perimeter = 100 cn
To find :
Area of the Rectangle
According to the question:
• Length - 1 & Width = w
It is given that. Length is 6 cm more than it's width / breadth,
16+ w
-- Perimeter of the Rectangle = 2(1+w)
- 100 -2 6 +w)+(w)
- 100 = 2(6+ 2w)
-100 = 12 +4w - 4w = 100 - 12
- 4w- 88
-w = 88 /4
W 22
Width = 22 cm
Length =6+ w6+22= 28 cm
Verification:
Perimeter 211.6)
100 - 2(28 + 22) 100 =2( 50)
Hence Verified!
Finding Area :
Area of the Rectangle (xb) )
-( 28 - 22)
616 cm
Answer:
616sq.cm.
Step-by-step explanation:
Let, width of the rectrangle be "x"
Thus according to the question,
2*{x+(x+6)}= 100
=x+(x+6) =50
=2x+6=50
=2x=44
=x=22
ie. width of the rectrangle is 22cm
so, length of the rectrangle is (22+6)=28cm
THUS AREA OF THE RECTRANGLE IS 22*28= 616sq.cm.
HOPE IT WILL HELP YOU...