Question

A rectangle has a perimeter of 100 cm.find the greatest possible area for the rectangle​

Answer 1

Answer:

624 sq cm

Step-by-step explanation:

We know the perimeter of rectangle = 2*(length + width) unit.

Here 2*(length + width) = 100 cm

So, length + width = 100/2 = 50 cm

In rectangle length is always bigger than width.

By assuming, If length & width equals, it becomes square and area is the biggest i.e. 25 * 25 = 625 sq cm.

But, length will be bigger. Hence greatest possible area of this rectangle will be if length is 26 cm and width is 24 cm. So area will be 26*24 = 624 sq cm.

hope this was the answer you were looking for

Answer 2

AnSwer -:


the greatest possible area for

the Rectangle is = 624 sq. cm

______________________________

_____________________________

Explanation-:

We know that ,

Perimeter of Rectangle = 2 (l + b)

L = length

B= breadth

So ,

Given ,

Perimeter of square-: 100 cm

Then ,

2 (L + B )=100 cm

L + b = 100 cm /2

L+ b = 50 cm

Then ,


In rectangle length is always bigger than

width.

By assuming length and width equal it

will become square and area =

Length of side of a square = 25

Or ,

Length of Rectangle = 25

Breadth of Rectangle = 25

Area of square = side x side

Area of Rectangle = length x breadth


25 x 25 =

= 625 sq . cm

But length will be bigger ,


Hence

greatest possible area of this rectangle

will be if

length is 26 cm

and

width is 24 cm.

Then Area of Rectangle = l x b

26 x 24 = 624 sq. cm

Therefore the greatest possible area for

the Rectangle is = 624 sq. cm

______________________________

Formulas related to the question-:


Area of Rectangle = length x breadth

Areas of square = side x side

______________________________