Question

a rectangle has a perimeter of 24cm and an area of 32 sq cn. what are the lengths of the sides of the rectangle​

Answer 1

Answer:

let l be the length

and b be the breadth

then 2(l+b)=24

l+b=12------------(1)

l*b=32

b=32/l -------------(2)

l+32/l

l^2 + 32=12l

l^2- 12l + 32=0--------(3)

now solving eq 3

l^2 -4l-8l+32=0

l(l-4) -8(l-4)=0

(l-4)(l-8)=0

: either l=4 and b=8

or

l=8 and b=4.