a rectangle has a perimeter of 320 m and its length is 3 times its width . find the Length, breadth and the area of the rectangle.
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Answer:
a rectangle piece of land measures 7m by 5m.each side is to be fenced with 4 rows of wire what is the length of the wire needed
The length, breadth, and area of the rectangle is 120 m, 40 m, and 4800 m² respectively.
• Let the length of the rectangle be l.
Let the width of the rectangle be w.
(Width means breadth of the rectangle)
• Given,
Perimeter of the rectangle = 320 m
Length is three times the width
=> l = 3w -(i)
• We know that the perimeter of a rectangle is given by the formula : 2 (length + width)
=> 320 m = 2 (l + w)
=> 320 m = 2 (3w + w) [Putting l = 3w, from (i)]
=> 320 m = 2 × 4w
=> 320 m = 8w
=> w = 320 m / 8
=> w = 40 m
Therefore, width of the rectangle is 40 m.
• Now, putting the value of w in (i), we get,
l = 3 × 40 m = 120 m
Therefore, the length of the rectangle is 120 m.
• Area of a rectangle is given by the formula : (length × width)
=> Area of the rectangle = 120 m × 40 m
=> Area = 4800 m²
Therefore, the area of the rectangle is 4800 m².