Question

a rectangle has a perimeter of 32cm

write down a possible pair of values of its length and width

Answer 1

Answer:

let the length be x and breadth be y

solution

perimeter of rectangle = 2x(l+b)

32=2x(x+y)

32÷2=x+y

16=x+y

:.x+y or l+b can be 10+6/1+15/2+14/3+13 and many more

☺Plz mark it as branliest answer

Answer 2

Given

• Perimeter of rectangle = 32cm.

To Find

• Length and breadth of rectangle

Concept

Here, we have given the perimeter. We want to find the length and breadth of the rectangle. First, we will apply the formula of Perimeter of rectangle and then by transposing we'll find the answer.

Solution

Perimeter of Rectangle = 2(length + breadth)

$\implies \sf 32 = 2(l+ b)$

$\implies \sf \frac{32}{2} = (l+ b)$

$\implies \sf 16 = (l+ b)$

Final Answer

So now, we need to find possible pairs when we've got the Lenght + Breadth = 16.

Possible pairs can be:-

$\rightarrow \sf 1. \: 16 = 10+ 6$

$\rightarrow \sf 2. \: 16 = 15+ 1$

$\rightarrow \sf 3. \: 16 = 14+ 2$

$\rightarrow \sf 4. \: 16 = 13+ 3$

$\rightarrow \sf 5. \: 16 = 12+ 4$

These can be possible pairs for the equation. There can be many more. By doing like this we can find more pairs.