Question

A rectangle has an area of 10cm2 if each side had its length tripled what would be the new area

Answer 1

Your Answer:

Given:-

• Area of rectangle = 10 cm^2
• Each length is tripled

To Find:-

• The new area

Solution:-

$\tt l \times b= 10cm^2 \\\\ \tt lb = 10cm^{2}$

Now new area

$\tt (3l)\times(3b) \\\\= \tt 9lb$

Now replacing values of lb

$\tt 9lb \\\\ \tt = 9(10) \\\\ \tt \blue{ = 90cm^2}$

So, the new are will be $\tt 90cm^2$

Answer 2

Answer:

90 cm² =

Step-by-step explanation:

we can assume the length to be 5 and the width to be 2 so that we have 5×2 = 10

triple of the sides = 5×3 = 15, 2×3 = 6

new area = 15 × 6 = 90 cm²

we can also try this with 10 and 1

10 × 3 = 30, 1 × 3 = 3

new area = 30 ×3 = 90cm²