Question

A rectangle has an area of 40in square. The length is 3 in longer than the width. Find the length and width

Answer 1

A=40
L=3+x
B=x(let).
A=L*B
40=x(x+3)=x2+3x
0=x2+3x-40
0=x2+8x-5x-40
0=x(x+8)-5)(x+8)
X=5
L=x+3=5+3=8
B=5