A rectangle has an area of k2 + 19k + 60 square inches. If the value of k and the dimensions of the rectangle are all natural numbers, which statement about the rectangle could be true?
Answers
Answered by
3
Thank you asking the question.
you should also give the options that will be helpful but still here is the answer.
first of all you should check quadratic to know the area of rectangular so that it can be factorized easily.
As we know that area of rectangular is given by using length and width( product of both) k2+19k+0 = (k+4)(k+15)
where k + 15 mean length of rectangular while k+4 means width of rectangular.
so width of rectangular is = k+ 4
length of rectangular is = k+15.
I hope this will help you.
you should also give the options that will be helpful but still here is the answer.
first of all you should check quadratic to know the area of rectangular so that it can be factorized easily.
As we know that area of rectangular is given by using length and width( product of both) k2+19k+0 = (k+4)(k+15)
where k + 15 mean length of rectangular while k+4 means width of rectangular.
so width of rectangular is = k+ 4
length of rectangular is = k+15.
I hope this will help you.
Answered by
2
Solution :-
k^2 + 19k + 60
k^2 + 19k + 60 = 0
k^2 + 15k + 4k + 60 = 0
k(k + 15) + 4(k + 15) = 0
(k + 15) (k + 4) = 0
So, the length of the rectangle is k + 15 and the width is k + 4
Answer.
k^2 + 19k + 60
k^2 + 19k + 60 = 0
k^2 + 15k + 4k + 60 = 0
k(k + 15) + 4(k + 15) = 0
(k + 15) (k + 4) = 0
So, the length of the rectangle is k + 15 and the width is k + 4
Answer.
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