A rectangle has an enclosed area of 40 and a perimeter of 18 sqrt 2. Find the length of a diagonal of the rectangle
Answers
Answered by
0
Area=L×b
40=L×b
perimeter=2(L+b)
20=2(40/b+b)
20/2=40+b^2/b
10×b=40+b^2
b^2-10b+40=0
there is solution for eqn
Similar questions