Question

A rectangle has length 22 mm and width 12 mm. If its length were increased by 7 percent sign and its width were increased by 6 percent sign, what would be the percentage increase in the rectangle's area?

Answer 1

length of rectangle , L = 22mm
width of rectangle , B = 12mm
so, area of rectangle = L × B = 22 × 12 = 264mm²

now, length was increased by 7 %
so, new length of rectangle = 22 + 7% of 22
= 22 + 154/100 = 22 + 1.54 = 23.54 mm

width was increased by 6 %
so, new width of rectangle = 12 + 6 % of 12
= 12 + 6 × 12/100 = 12.72 mm

so, area of new rectangle = 23.52 × 12.72 mm²
= 299.1744 mm²

change in area = 35.1744 mm²

% change in area = 35.1744/264 × 100 = 13.32 %

Answer 2

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HERE'S YOUR ANSWER


ANSWER :-

13.32 %



EXPLAINATION :-

L = 22mm

B = 12mm

So, area of rectangle = L × B => 22 × 12

=> 264mm²

Now, length was increased by 7 %

So, new length of rectangle = 22 + 154/100

=> 22 + 1.54

=> 23.54 mm

Breadth was increased by 6 %

So,

New width of rectangle = 12 + 6 × 12/100

=> 12.72 mm

So,

Area of new rectangle = 23.52 × 12.72 mm²

= 299.1744 mm²

Change in area = 35.1744 mm²

In % = 35.1744/264 × 100

=> 13.32 %