a rectangle has length 50 cm and breadth 45 CM square has its side 48 cm which has more area and by how much
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area of rectangle=l*b
=50*45=225cmsq
area of square=asq
=48*48=2304
hence area of square is more than the area of rectangle that is 2304 -225 is equals to 2079
hope this answer is correct and it will help you thank
=50*45=225cmsq
area of square=asq
=48*48=2304
hence area of square is more than the area of rectangle that is 2304 -225 is equals to 2079
hope this answer is correct and it will help you thank
ziaahmad:
thanks
Answered by
2
Answer:
Area of rectangle = length × b.
= 50 cm × 45 cm
= 2250 sq.cm
Area of square = side × side
= 48 cm × 48 cm
= 2304sq.cm
Area of square is more than area of rectangle by 54sq.cm
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