A rectangle has length 50 cm square has side 20 m find which shape has more perimeter if both have same area
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ANSWER:
- Perimeter of rectangle> perimeter of square.
GIVEN:
- Length of rectangle = 50 cm
- Side of square = 20 m
TO FIND:
- Which have more perimeter.
SOLUTION:
Area of rectangle = Area of square (given)
here:
length of rectangle is 50 cm = 50/100 = 0.5 m
Let the breadth of rectangle be x
Area of rectangle = (0.5)*x
Area of square = (20)*(20)
Now
=> (0.5)x=20*20
=> x = 400/0.5
=> x = 4000/5
=> x= 800 m
So breadth of rectangle = 800m
perimeter of rectangle = 2(l+b)
= 2(0.5+800)
=(800.5)*2
=1601 m
Perimeter of square = 4*(side)
=4(20)
=80m
Here
- perimeter of rectangle> perimeter of square.
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