Question

a rectangle has length two more then 5 times its breadth and its perimeter is 52cm then the are is what

Answer 1

Answer:

Let the breadth be b

length of 5b+2

Perimeter of rectangle =2(length +breadth)

52 = 2(5b+2+b)

52= 2(6b+2)

52= 12b+4

52-4 =12b

48=12b

b=48÷12

b=4

breadth =4 ,length,= 22

area of rectangle =length ×breadth

=4×22

=88 cm²