Question

a rectangle has length which is 5cm less than twice it's braedth .if the length is decreased by 5cm and breadth is increased 2cm the perimeter of the reuslting rectangle will be 74cm . find the length and breadth of the original rectangle

Answer 1

let the length of original rectangle be
" L " and breadth be "B"

original breadth = B cm

original length L = ( 2B - 5 ) cm -eq(1)

according to question ,
if the length is decreased by 5cm and breadth is increased by 2 cm

new length = (2B - 5 ) - 5= 2B- 10

new breadth = B + 2

resulting perimeter of rectangle=74 cm

2( new length + new breadth) = 74 cm

2 (2B - 10 + B + 2 ) = 74

( 3B - 8 ) = 74/2

3B - 8 = 37

3B = 45

B = 15 cm

put Value of " B " in eq(1) , we get

L= (2(15) - 5 )

L = 25 cm

therefore , length of original rectangle
= 25 cm and breadth = 15 cm
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Your Answer: L=25cm, B = 15cm
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