Question

A rectangle has perimeter 132cm its
length is 9 cm more than twice its
width. Find its area?​

Answer 1

Answer:

893 cm^2

Step-by-step explanation:

Perimeter of a rectangle = 132 cm

Length of the rectangle = 9 + 2(width)

Let width of the rectangle be x cm

Width of the rectangle = x cm

Perimeter of rectangle = 2(Length × Breadth)

132 = 2(9+2x +x)

132 = 18 + 6x

132 - 18 = 6x

114 = 6x

114/6 = x

Hence x = 19

So, Width is 19 cm

Length = 9+ 2( 19 )

= 9+ 38

= 47 cm

Area of the rectangle = Length × Breadth

= 47 × 19

= 893 cm^2

Hope u understood