Question

A rectangle has perimeter 24cm and length 9cm . find its breadth and area.​

Answer 1

Answer:

Breadth of the rectangle is 3 cm and the area of the rectangle is 27 cm².

Step-by-step explanation:

Given :-

• Perimeter of rectangle = 24 cm
• Length of rectangle = 9 cm

To find :-

• Breadth and area of the rectangle.

Solution :-

Formula used :

•${\boxed{\sf{Perimeter\:of\: rectangle=2(length+Breadth)}}}$

• ${\boxed{\sf{Area\: of\: rectangle=length\times\: breadth}}}$

Let the breadth of the rectangle be x cm.

According to the question,

2(9+x) = 24

→ 9+x = 24/2

→ 9+x = 12

→ x = 12-9

→ x = 3

Therefore, breadth of the rectangle is 3 cm.

Area of the rectangle,

= length × breadth

= (9× 3) cm²

= 27 cm²

Therefore, area of the rectangle is 27 cm².

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★ ${\underline{\sf{\blue{More\:Info:}}}}$

• Area of square = side²
• Perimeter of square = 4× side
• Diagonal of rectangle = √(length² + breadth²)

Answer 2

$\tt {\pink{Given}}\begin{cases} \sf{\green{Perimeter \: of \: rectangle =24 \: cm}}\\ \sf{\blue{Length \: of \: rectangle = 9 \: cm}}\\ \sf{\orange{Breadth \: of \: rectangle= \: ?}}\\ \sf{\red{Area \: of \: rectangle= \: ?}}\end{cases}$

⚽ Diagram :

$\setlength{\unitlength}{3 mm}</p><p>\thicklines\begin{picture}(12,8) \put(1,1){\line(2,0){20}}\put(1,10){\line(2,0){20}}\put(1,1){\line(0,1){9}}\put(21,1){\line(0,1){9}}\put(1,1){\line(2,0){20}}\put(1,10){\line(2,0){20}}\put(1,1){\line(0,1){9}}\put(21,1){\line(0,1){9}}\put(1,1){\line(2,0){20}}\put(1,10){\line(2,0){20}}\put(1,1){\line(0,1){9}}\put(21,1){\line(0,1){9}}\put(1,1){\line(2,0){20}}\put(1,10){\line(2,0){20}}\put(1,1){\line(0,1){9}}\put(21.5,5){\sf(Length = 9 cm)}\put(7.5,0){\sf(Breadth = ?)}\put(5.5,5){ \boxed{{\boxed{ \tt {MystifiedBoy}}}}}\end{picture}$

Answer:

Let the Breadth be x cm.

____________________

☯ $\underline{\boldsymbol{According\: to \:the\: Question\:now :}}$

$:\implies\sf Perimeter \: of \: rectangle =24 \: cm$

$:\implies \sf 2(Length + Breadth) = 24 cm$

$:\implies \sf 2(9 + x) = 24 cm$

$:\implies \sf 18 + 2x= 24 cm$

$:\implies \sf 2x= 24 - 18$

$:\implies \sf 2x= 6$

$:\implies \underline{ \boxed{\textsf{ \textbf{ x = 3 cm}}}} \qquad\Bigg\lgroup \textsf{Breadth of rectangle}\Bigg\rgroup$

$\therefore{\underline{\textsf{Breadth of rectangle is \textbf{3 cm}}}}.$

_____________________

$\dashrightarrow\:\: \sf Area \: of \: rectangle = Length \times Breadth$

$\dashrightarrow\:\: \sf Area \: of \: rectangle = 9\times 3$

$\dashrightarrow\:\: \underline{ \boxed{\textsf{ \textbf {Area of rectangle = 27 cm ^{3} }}}}$

$\therefore{\underline{\textsf{Area of rectangle is \textbf{27 cm ^3 }}}}.$