a rectangle has the length of a 50 cm and breadth of 45 CM square has its side 38 CM which has more area and by how much
Answers
Answer:
Given :-
length of rectangle = 50 cm
breadth of rectangle = 45
side of square = 38 cm
To find :-
area of rectangle = ?
area of square = ?
there are two possibilities in this question , either rectangle has more area than square or square has more area than rectangle .
AREA OF RECTANGLE = length × breadth
= 50 × 45
= 2250 cm^2
AREA OF SQUARE = side^2
= 38^2
= 1444 cm^2
RECTANGLE has more area than the square ..
This is your answer..
Answer:
Area of Rectangle is greater than area of square by 806 cm².
Step-by-step explanation:
Given :
For Rectangle:
length = 50 cm
breadth = 45 cm
For Square:
side of square = 38 cm
To Compare : Areas of Rectangle and Square.
We know that,
Area of Rectangle = Length x Breadth
so, area of Rectangle= 50 x 45 cm² = 2250 cm2
Area of square = (side)²
so, area of square = 38² cm² = 1444 cm²
Hence we can see 2250 > 1444
Difference = 2250 - 1444 cm² = 806 cm²
so, area of Rectangle is greater than area of square by 806 cm².