Math, asked by shraddhamandloi25, 11 months ago

a rectangle has the length of a 50 cm and breadth of 45 CM square has its side 38 CM which has more area and by how much​

Answers

Answered by mantasakasmani
6

Answer:

Given :-

length of rectangle = 50 cm

breadth of rectangle = 45

side of square = 38 cm

To find :-

area of rectangle = ?

area of square = ?

there are two possibilities in this question , either rectangle has more area than square or square has more area than rectangle .

AREA OF RECTANGLE = length × breadth

= 50 × 45

= 2250 cm^2

AREA OF SQUARE = side^2

= 38^2

= 1444 cm^2

RECTANGLE has more area than the square ..

This is your answer..

Answered by DSamrat
12

Answer:

Area of Rectangle is greater than area of square by 806 cm².

Step-by-step explanation:

Given :

For Rectangle:

length = 50 cm

breadth = 45 cm

For Square:

side of square = 38 cm

To Compare : Areas of Rectangle and Square.

We know that,

Area of Rectangle = Length x Breadth

so, area of Rectangle= 50 x 45 cm² = 2250 cm2

Area of square = (side)²

so, area of square = 38² cm² = 1444 cm²

Hence we can see 2250 > 1444

Difference = 2250 - 1444 cm² = 806 cm²

so, area of Rectangle is greater than area of square by 806 cm².

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