Question

A rectangle has the perimeter 90 cm and the width 13 cm less then the length. What is the area of the rectangle?

Answer 1

Answer:

464cm^2

Step-by-step explanation:

p = 2(l+b)

90 = 2(l+l-13)

90/2=2l-13

45 = 2l-13

45+13=2l

58=2l

58/2=l

29=l

b=29-13

b=16

area=l×b

area=29×16

area=464cm^2

Answer 2

Given,

Perimeter of the rectangle = 90 cm

Width is 13cm less than the length.

To find,

The area of the rectangle.

Solution,

We can simply solve this mathematical problem by using the following mathematical process.

Let, the length of the rectangle = x cm

So, the width of the rectangle = (x-13) cm

Perimeter of the rectangle = 2 × (x+x-13) = (4x-26) cm

According to the data mentioned in the question,

4x-26 = 90

or, 4x = 90+26

or, 4x = 116

or, x = 116/4

or, x = 29

Length is = 29 cm

Width will be = 29-13 = 16 cm

Area will be = Length × Width = 29×16 = 464 cm²

Hence, the area of the rectangle is 464 cm².