Math, asked by ritaleo02, 8 months ago

a rectangle has the same area as another whose length is 6 m more and breadth is 4m less it has also the same area as the third whose length is 8m more and Breadth 5m less find the lengthy and breadth of the original rectangle​

Answers

Answered by harshchavan11
1

Answer:

length is 28 and breath is 20

Step-by-step explanation:

Let , Lenght be x and Breath be y

Area of Rectangle = length × breath

= xy

According to the first condition ,

xy = ( x + 6) ( y - 4 )

xy = xy - 4x + 6y - 24

xy - xy = - 4x + 6y - 24

- 4x + 6y = 24

4x - 6y = ( - 24 )

Dividing by 2 both side ,

2x - 3y = ( - 12 ) ......... 1st equation

According the the second condition ,

xy = ( x + 8 ) ( y - 5 )

xy = xy - 5x + 8y - 40

xy - xy = - 5x + 8y - 40

- 5x + 8y = 40

5x - 8y = ( - 40 ) .......... 2nd equation

Multiply equation ( 1 ) by 5

10x - 15y = ( - 60 ) ........ 3rd equation

Multiply equation ( 2 ) by 2

10x - 16y = ( - 80 ) ....... 4th equation

Subratct equation ( 3 ) From ( 4 )

10x - 16y = - 80

10x - 15y = - 60

_________________

- y = - 20

y = 20

put value of y in equation 3rd

10x - 15 ( 20 ) = - 20

10x - 300 = - 20

10x = - 20 + 300

10x = 280

x = 280 ÷ 10

x = 28

therefore , length of rectangle is 28 and breath is 20

Answered by varadvarmal
1

Answer:

Step-by-step explanation:

Attachments:
Similar questions