Question

A rectangle has the same area as that of a square of length 10 m. If the breadth of
the rectangle be 8 m, find the perimeter of the rectangle.​

Answer 1

Given :

• Side of a square is 10m

• Breath of the rectangle is 8m

To Find :

• Perimeter of the rectangle = ?

Solution :

Here, it's given that :

• Area of square = Area of rectangle

Now,

As we know that,

• Area of square = side × side

Putting the values,

→ Area of square = 10 × 10

→ Area of square = 100 cm²

_________________________

➠ Area of rectangle = length × breath = 100

➠ Area of rectangle = l × 8 = 100

➠ Area of rectangle = l = 100/8

➠ Area of rectangle = 12.5

Now,

We know that,

• Perimeter of rectangle = 2(l + b)

Putting the values,

➨ 2 (12.5 + 8)

➨ 2 (20.5)

➨ 41 cm

Hence, the perimeter of the rectangle is 41 cm

Answer 2

Given :

$\tt\ \: length\: of \: square \: = 10m$

$\tt \: breadth \: of \: rectangle \: = 8m$

$\tt \: area \: of \: rectangle \: = area \: of \: square$

To Find :-

$:= \tt \: perimeter \: of \: rectangle$

Solution :-

$\: \tt \: as \: area \: of \: square \: = area \: of \: rectagle$

So,

$\small{\underline{\boxed{\tt{\blue{area_{\: (square) \: = side \times side}}}}}}$

$\small{\underline{\boxed{\tt{\green{area_{\: (square) = 10 \times 10m}}}}}}$

$\tt \: = 100 {m}^{2}$

$= \tt {\pink {\: area \: of \: square \: = 100 {m}^{2} }}$

So now,

$\small{\underline{\boxed{\tt{\orange{area_{\: (rectangle) = length \times breadth}}}}}}$

$\small{\underline{\boxed{\tt{\pink{area_{\: (rectangle = 100 {m}^{2} ) = l \times 8m}}}}}}$

$\small{\boxed{\tt{\blue{100 {m}^{2} \div 8 = l}}}}$

$\small{\boxed{\tt{\green{12.5 = l}}}}$

So,

$\tt \: perimeter \:rectangle = 2 \times l + b$

$\tt \ \: perimeter \: = 2 \times 12.5 + 8$

$\tt \: perimeter \: = 41m$

answer = 41m